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Linear advance 1.5  

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coolRR
(@coolrr)
Trusted Member
Linear advance 1.5

Hi everyone,

I was very happy to see the new firmware update, but I was a little confused about the optimal settings for Linear Advance 1.5.

Currently I use `M900 K30` for PLA and `M900 K45` for PETG. (Using Simplify3D.) I understand that the new change is backward compatible and that's good. But assuming I want to take advantage of the new Linear Advance 1.5 feature. What would you recommend as thew new M900 lines to use?

 

 

Thanks for your help,

Ram Rachum.

Posted : 28/05/2020 9:32 am
Neophyl
(@neophyl)
Illustrious Member
RE: Linear advance 1.5

iirc 30 equates to 0.6 on the new profiles for PLA.  Not sure about PETG.  You could run the linear K test from Marlin to see whats actually best for that particular filament/printer combo and set the filament profile to contain the optimised value.

https://marlinfw.org/tools/lin_advance/k-factor.html

Posted : 28/05/2020 10:42 am
vintagepc
(@vintagepc)
Member
RE: Linear advance 1.5

Definitely best to calibrate it per-filament, but PETG values will be 0.08-0.12

Edit: Also, PLA is 0.06, not 0.6 if memory serves.

Posted : 28/05/2020 2:05 pm
coolRR
(@coolrr)
Trusted Member
Topic starter answered:
RE: Linear advance 1.5

@vintagepc

So that would mean a line like M900 K0.1 ?

Posted : 28/05/2020 2:08 pm
Lichtjaeger
(@lichtjaeger)
Noble Member
RE: Linear advance 1.5

Why don't you simply use the expression from the current Prusa PLA profiles?

M900 K{
if printer_notes=~/.*PRINTER_MODEL_MINI.*/ and nozzle_diameter[0]==0.6}0.12{
elsif printer_notes=~/.*PRINTER_MODEL_MINI.*/}0.2{
elsif nozzle_diameter[0]==0.6}0.04{
else}0.06{endif} ; Filament gcode LA 1.5
{if printer_notes=~/.*PRINTER_MODEL_MINI.*/};{elsif printer_notes=~/.*PRINTER_HAS_BOWDEN.*/}M900 K200{
elsif nozzle_diameter[0]==0.6}M900 K18{
else}M900 K30{endif} ; Filament gcode LA 1.0
Posted : 28/05/2020 2:25 pm
Neophyl
(@neophyl)
Illustrious Member
RE: Linear advance 1.5
Posted by: @vintagepc

Definitely best to calibrate it per-filament, but PETG values will be 0.08-0.12

Edit: Also, PLA is 0.06, not 0.6 if memory serves.

Sorry, damn memory - getting old 🙂  I was only out by a decimal place lol.

Posted : 28/05/2020 2:40 pm
coolRR
(@coolrr)
Trusted Member
Topic starter answered:
RE: Linear advance 1.5

Thank you! 

Posted : 28/05/2020 3:31 pm
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